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Jan 28, 11:08 PM
#1

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Nov 2019
132
We all know that:


  • voting paper from the drawer has lower priority
  • not voting/voting blank/unrecognisable writing/non-existing player name will be count as self voting
  • if a player vote with more than one paper not as the same time then only the first one getting in will be counted
  • if a player vote with more than one paper and it's impossible to tell which one go first then only the first one coming out will be counted
  • there could be a final voting if thing still can't be settled
  • the number of surviving players being in odd number matters



Okay I get the rules of the voting thing but I don't understand why does participants being in odd number matters for a final voting.
I'm asking this because what I really want to ask is that what if every player voted to exactly one different person and all/none of them lost their paper?

i.e. what if everyone votes:


  • only once
  • in circle
  • the same value level of voting paper



If this happens then what? A final round will happen and solve it?
Jan 28, 11:46 PM
#2
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May 2022
43
ur thinking way too hard about this bro
Jan 29, 12:14 AM
#3
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Sep 2024
26
5 participants voting for 2 people can only be
5-0
4-1
or 3-2.

and you are really thinking WAAAAAY to hard bro
Jan 29, 12:21 AM
#4

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Jul 2021
359
that's a tie, so the vote will continue until the tie breaks. isn't it obvious?

the odd number is relevant in that the tie breaker could only last one round if it were the case that 2 people tied. They probably didn't consider the possibility of a 5 way tie happening, which would've required the girls to find out about the game, discuss it, and cooperate, risking betrayal.

I'm sure that a 5 way tie would've carried on for a couple of rounds until the gms would arbitrarily pick one of them, probably based on the first paper to be deposited.
Jan 29, 1:12 AM
#5

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Nov 2019
132
Reply to HOnline23
5 participants voting for 2 people can only be
5-0
4-1
or 3-2.

and you are really thinking WAAAAAY to hard bro
@HOnline23 I'm talking about a result of 1-1-1-1-1, whether by cooperation or by chance.
Jan 29, 1:16 AM
#6

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Jan 2021
2752
I would like to think it is some kind of secret ending where everyone is saved.
Jan 29, 1:34 AM
#7

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Nov 2019
132
Reply to IhnalakoKaina
that's a tie, so the vote will continue until the tie breaks. isn't it obvious?

the odd number is relevant in that the tie breaker could only last one round if it were the case that 2 people tied. They probably didn't consider the possibility of a 5 way tie happening, which would've required the girls to find out about the game, discuss it, and cooperate, risking betrayal.

I'm sure that a 5 way tie would've carried on for a couple of rounds until the gms would arbitrarily pick one of them, probably based on the first paper to be deposited.
@IhnalakoKaina Rather than the gm picking one, my guess will be the "audiences" will do an additional round.

BTW 2 out of 5 players had already known from the start in this game.
If all 5 players in the group know each other like the 4 in the actual show, and their lead is one of those who figured it out fast, the tie could actually happen. The leader could tell the whole group about the voting game, how to vote a 5 way tie, and time to brace themselves way before doing the walk.
But of course avoiding serious mistakes caused by emotion and pride, and refusing abandoning teammates like what mishiro did would be necessary to make the others to trust your plan and not betray out of fear out of being betrayed.
Jan 29, 1:37 AM
#8
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Feb 2021
250
HaruyukiIsCute said:
@HOnline23 I'm talking about a result of 1-1-1-1-1, whether by cooperation or by chance.

Just speculation but it prob would be keep voting until one person has the most. This is because they would be trap and can’t leave until someone dies so they either keep getting 1-1-1-1-1 and be trapped or someone dies
Jan 29, 6:10 AM
#9
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Jul 2021
242
Agree with the last post. There’s no indication they’ll get to leave until voting is finished and eventually someone is going to cave under pressure or fear that someone else is going to break the voting pattern before them. If a tie doesn’t save them, there’s no incentive to cooperate.
Jan 29, 6:30 AM

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Mar 2023
843
Reply to HaruyukiIsCute
@HOnline23 I'm talking about a result of 1-1-1-1-1, whether by cooperation or by chance.
@HaruyukiIsCute In such a case tie breaker is only between those that got voted using the "strong" votes.
The ones that got voted with drawer paper become safe, which reduces the number of participants for the tie breaker.

At this point there is either 2 or 3 left, 2 ends at next tie break and 3 could need 1 more tie break in the 2-2-1 case.
Only loophole I see, is what happens if a person that is now safe refuses the vote. That makes it less than 5 votes and breaks the game, unless there is another rule for that.
watsymJan 29, 6:36 AM
Jan 29, 8:25 AM
Offline
Nov 2018
1918
HaruyukiIsCute said:
@HOnline23 I'm talking about a result of 1-1-1-1-1, whether by cooperation or by chance.

I'm pretty sure one of the rules was even if there was a tie it will keep going until there wasn't a tie. So if you kept getting ties the voting would go indefinitely until there wasn't one.
Jan 29, 9:20 AM
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May 2024
1127
if they knew the 6th girls name they could have voted her, that's the loophole but they didn't because she pre died ...
Jan 29, 2:43 PM
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May 2021
3
DeityNyxCiara-_- said:
if they knew the 6th girls name they could have voted her, that's the loophole but they didn't because she pre died ...

they couldn’t vote for her, the rules said voting for someone who’s not in the room isn’t allowed
Jan 29, 11:01 PM
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Dec 2025
2
watsym said:
@HaruyukiIsCute In such a case tie breaker is only between those that got voted using the "strong" votes.
The ones that got voted with drawer paper become safe, which reduces the number of participants for the tie breaker.

At this point there is either 2 or 3 left, 2 ends at next tie break and 3 could need 1 more tie break in the 2-2-1 case.
Only loophole I see, is what happens if a person that is now safe refuses the vote. That makes it less than 5 votes and breaks the game, unless there is another rule for that.

I think they said that if someone refuses to vote it will count as a vote for themself
Jan 30, 12:18 AM
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Sep 2021
50
Odd numbers matter because it's not divisible by two, and the teddy already gave us the answer for how the tie breakers will go
Votes on original papers will be stronger, and in the case of a second tie, a runoff where (I assume) someone is picked at random will take place.
In any case, someone will die in the end

For your hypothetical situation, the game makers will pick someone by random or by having an internal voting.
Jan 30, 5:35 AM
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May 2013
17
The Voting Analysis

  1. Mishiro-Lost paper when wolf stole backpack.
    Voted for Chie(drawer)
  2. Kotoha-Had original paper. When Yuki picked her up, Yuki gave her the paper from the backpack and told her not to lose it, as they both seemed aware of it's purpose.
    Voted for Keito(orig) (Promised not to vote for Chie)
  3. Chie-May have had original paper.
    Vote not disclosed(orig?) (Promised not to vote for Kotoha)
  4. Keito-May have had original paper.
    Voted for Kotoha(orig?)
  5. Yuki-Had own original paper, and picked up the paper from the 6th girl that died on the stairs, and likely picked up the paper after Mishiro ran away from the wolf. Thus 3 original papers + 1 drawer paper.
    Voted 4 papers, one was not orig.

Step 1:

  1. Mishiro

    • ?-Yuki(orig or drawer)
    • ?-Chie(orig?)

  2. Kotoha

    • +1-Keito(orig?)
    • ?-Yuki(orig or drawer)

  3. Chie

    • +1-Mishiro(drawer)
    • ?-Yuki(orig or drawer)

  4. Keito

    • +1-Kotoha(orig)
    • ?-Yuki(orig or drawer)
    • ?-Chie(orig?)

  5. Yuki

    • ?-Chie(orig?)


So Chie, having been voted for by Mishiro, could have only received 2 votes max. (She wouldn't vote for herself).
Mishiro's vote for her was a drawer vote, a weaker vote. So the only way she could be highest was by getting Yuki's vote, as Keito had been voted for by Kotoha with an original paper (stronger vote).


Step 2:

  1. Mishiro

    • ?-Chie(orig?)

  2. Kotoha

    • +1-Keito(orig?)

  3. Chie

    • +1-Mishiro(drawer)
    • +1-Yuki(orig or drawer)

  4. Keito

    • +1-Kotoha(orig)
    • ?-Chie(orig?)

  5. Yuki

    • ?-Chie(orig?)


Chie received +1 by Mishiro (drawer) and +1 by Yuki (drawer or orig)
Keito received +1 by Kotoha (orig), so if she received any more votes, it would have been a tie or she would have been higher.
Kotoha received +1 by Keito (orig or drawer?), Chie promised not to vote for her.



Step 3:

  1. Mishiro

    • ?-Chie(orig?)

  2. Kotoha

    • +1-Keito(orig?)

  3. Chie

    • +1-Mishiro(drawer)
    • +1-Yuki(orig or drawer)

  4. Keito

    • +1-Kotoha(orig)

  5. Yuki

    • ?-Chie(orig?)


So Chie voted for Mishiro or Yuki, but she showed more dislike for Mishiro.



So the likely voting was::

  1. Mishiro

    • +1-Chie(orig?)

  2. Kotoha

    • +1-Keito(orig?)

  3. Chie

    • +1-Mishiro(drawer)
    • +1-Yuki(orig or drawer)

  4. Keito

    • +1-Kotoha(orig)

  5. Yuki

    • 0

Jan 30, 1:32 PM

Offline
Jan 2021
3415
If there's a tie then they'll keep going until there's a loser, this rule you yourself mentioned [there could be a final voting if thing still can't be settled] is practically that. People saying you're thinking too hard are wrong, it's fine to talk about hypotheticals even if they wouldn't happen given the voting's circumstances in the anime.
Jan 31, 9:30 AM

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Apr 2012
24922
Reply to Ionliosite2
If there's a tie then they'll keep going until there's a loser, this rule you yourself mentioned [there could be a final voting if thing still can't be settled] is practically that. People saying you're thinking too hard are wrong, it's fine to talk about hypotheticals even if they wouldn't happen given the voting's circumstances in the anime.
@Ionliosite2 The key to this game's logic is that this arc is meant to show that Yuki isn't actually a cold, cynical player, but a person capable of empathy and a desire to help others escape. And how this clashes with reality. So we got something that Yuki wanted to save and even felt sympathy for Mishiro, although one still had to become the scapegoat.
Jan 31, 8:43 PM
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May 2024
1127
Reply to NotBony
DeityNyxCiara-_- said:
if they knew the 6th girls name they could have voted her, that's the loophole but they didn't because she pre died ...

they couldn’t vote for her, the rules said voting for someone who’s not in the room isn’t allowed
@NotBony I meant could have dragged her body in...
Jan 31, 9:27 PM

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Nov 2019
132
DeityNyxCiara-_- said:
@NotBony I meant could have dragged her body in...

I think
If
Someone thought that well to drag the body from the starting floor by
Either
Knowing what would happen through the hints
Or
Simply being cautious to prepare for any possibilities
Then
Whether the game master allow it or not while stating the rules could be affected by how the audience reacted.

The audience could go either way. They might think this loophole is ridiculous and anti-dramatic, or find it interesting to see a clever attempt.
Feb 1, 8:39 AM
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May 2024
1127
Reply to HaruyukiIsCute
DeityNyxCiara-_- said:
@NotBony I meant could have dragged her body in...

I think
If
Someone thought that well to drag the body from the starting floor by
Either
Knowing what would happen through the hints
Or
Simply being cautious to prepare for any possibilities
Then
Whether the game master allow it or not while stating the rules could be affected by how the audience reacted.

The audience could go either way. They might think this loophole is ridiculous and anti-dramatic, or find it interesting to see a clever attempt.
@HaruyukiIsCute It wouldn't take too long, because over one hour remains so they could go back, someone can climb someone else's soldiers to get to floor three because stairs were broken... Than Yukki might've so op that she learned the place of every trap... So I think it would be reasonable... 70 percent death rrate means one gotta die and a second maybe at the least... And why would there be 6 pods in the end unless to hint that, I think every game has a loophole but we gotta find it ourselves... In the 2nd game of Ep 1 I think that passing the key to person on the ryt and repaying would have saved everyone... But alas the survival rate was always meant to be 50 %

I'm legit waiting for Vol 5 to be translated to see Yukki in game 60 and sh!t...
Feb 5, 4:25 AM
Offline
Aug 2018
125
The game seems to be organized by people running a show, not a magical mascot character bound by fixed rules. They'd adapt to any scenario with the goal of making it fun for the audience.

Indeed, an odd number of players does not guarantee a runoff tiebreak. Players determined to get a tie (why?) could vote 2-2-invalid(self) and get an infinite tie. So that statement is just organizers motivating the players to vote, or even not realizing it themselves in the moment.

But in the first place, the rules and tiebreaks are not there to prevent a perfectly cooperating group from arranging a tie. It's to let competing players to vote somebody out.

The organizers chose who plays this game. They've stacked the odds with a large group of 4 against 2 solos, probably because it's fun and good for business.

If both solos died on the way, there's no way Mishiro's group would draw. Keito would try to vote either Chie or Kotoha out and then lie about it.

If by some magical coincidence the survivors were all goody two shoes and try to arrange an infinite draw, the organizers would just come up with a new tiebreak rule. Or just say "if you insist, in the next voting round *everyone* with the top vote will get gassed" and call it a day.
casual42Feb 5, 4:33 AM

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